See Answer. You'll get a detailed solution from a subject matter expert that helps you learn core concepts. F = ab' + bc + a'bc a b. b. Expand wx to sum-of-minterms form wxy+wxy' 1. It generates the sum of minterms expression F = Σ m (1, 5, 9). For SOP put 1’s in blocks of K-map respective to the minterms (0’s elsewhere). , logical-AND) of all of the signals, using the complement of any signal that needs to be False for that combination of inputs. 1 – Minterms = minterms for which the function F = 1. 7. In the given function F(A, B, C) = AB+B(A+C), the minterms are AB and B(A+C). Boylestad. Electrical Engineering. Implement the sum of minterms of this function and connect a, b, c and d to 0, 1, 0 and clock, respectively. 12. I want to ask that if we are told to express an Boolean Expression in sum of min-terms which is already in non-standard SOP form. The X and Y are the inputs of the boolean function F whose output is true when any one of the inputs is set to true. 4. Go through each of the possible inputs with both circuit outputs on the same waveform and explain how the waveform indicates the equations are the same. e. 2. Using the K-map provided in Fig. (e) Simplify E and F to expressions with a minimum of literals. DNF and CNF missing law/rule. Author: Robert L. F(x,y,z) = xyz Is the given equation in the canonical sum of minterms form? If not, convert it into this form. It is a Boolean expression containing AND terms called product terms with one or more literals each. 2. Previous question Next question. Literal can. So how can we show the operation of this “product” function in Boolean Albegra. 3. 3. 4. Trending now This is a popular solution! Step by step Solved in 2 steps. egin {tabular} {|c|c|c|} hlinex & y & f (x,y) hline 0 & 0 & 1. What is the minimum number of 2-input NOR gates required to implement 4-variable function expressed in sum-of-minterms from as f = Σ(0, 2, 5, 7, 8, 10, 13, 15)? Assume that all the inputs and their complements are available. 14 a Show minterms 3 2 1 00111 01000 a. Use Karnaugh maps to simplify the following Boolean functions expressed in the sum of minterms. (d) Obtain the function F as the sum of. In addition, you must show your work on the paper you submit on eLearning to get credit. g. Select the K-map according to the number of variables. Both equations simply list the minterms or maxterms present in a given truth table after the initial symbol. For example, consider the truth table in Figure 3. B 1 0 m2 = A . This product is not arithmetical multiply but it is Boolean logical AND and the Sum is Boolean logical OR. Draw circuit in Logisim. 2: Representing a Boolean function by a sum of minterms. Since all the variables are present in each minterm, the canonical sum is unique for a given problem. Step2: Add (or take binary OR) all the minterms in. Write the following expression as a sum of minterms: f(x,y,z)=xyz^'+x^' z+y, then simplify. Chapter 2. Step 2. 14. Sorted by: 2. (e) Using Boolean algebra, derive a simplified sum of products expression. (A*-B)+ (-A*B) = XOR. b. Show transcribed image text. Both have their uses depending on the situation. F (a,b,c) = a'c' + a'c + bc'. In SOP, ANY of those minterms can be true and the whole Function would be 1 because 1+X=1 This is the intuition behind SOP being positive logic and hence automatically, its complement, POS. 2. I am struggling to convert the sum of maxterms: ((¬b ∧ ¬d) ∨ ((b ∧ (¬c ∧ d)) ∨ (¬a ∧ (b ∧ d)))) into a product of minterms. Here is an outline of a possible approach: First, you should create a more convenient representation of the expression - for example, the expression could be a list of instances of a Minterm class, and Minterm could contain a list of instances of an Atom class, each of which could contain a char that tells which variable it is and a boolean that tells whether the variable is negated or not. It is a sum of all variables in a function and that function has the property that it is equal to 0 on exactly one row of that truth table. A function that defines the solution to a problem can be expressed as a sum of minterms (SoM) in which each of the minterms evaluates to. Express F in sum of minterms and product of maxterms. So for x'y' there exists two options of 00- where z is 000 and 001. w=xy+x′yz+y′z′ b. For. – A function can be written as a product Canonical Sum or Sum of Minterms (SoM) a sum of products in which each product term is a minterm. qx3zqy7 Jump to level 1 1 a b с у 2 0 0 0 0 3 0 0 1 1 0 1 0 0 0 1 1 0 5. Obtain the truth table for the function. Equivalent functions will have the same sum-of-minterms representation. Groups must be a power of 2. A sum-of-products form must be a sum of minterms and a minterm must have each variable or its compliment as a factor. I must solve this by using boolean algebra rules but i dont know how. 3. 2. In Figure P2. [c] Write the short form Sum of Products (SOP) expression (list minterms). 2. bad 0 0 0 0 0 0 0 10 b. Implement the sum of minterms of this function and connect a, b, c and d to clock. Here’s the best way to solve it. Its De Morgan dual is a " Product of Sums " ( PoS or. • product-of-maxterms • Expand the Boolean function into a. For the Boolean functions F(X,Y,Z) and E(X,Y,Z), as given in the following truth table: (a) List the minterms of F(b) List the maxterms of E(c) List the minterms of E' (d) List the maxterms of F⋅E(e) Express the Standard Sum of Product (SSOP) form of F(f) Express the Standard Product of Sum (SPOS) of F⋅EThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. ∗ (b+cd) (c+bd) 2. Often sum-of-product expressions may be simplified, but any nontrivial simplification will produce an expression that is not in sum-of-product form. For the Boolean functions E and F, as given in the following truth table: List the minterms and maxterms of each function. 1a, it is possible to represent only 14 minterms. Step 3. Two dual canonical forms of any Boolean function are a "sum of minterms" and a "product of maxterms. 3, note that minterm 0 (000 2) is just above minterm 4 (100 2). Write a function f(x) to represent the cost of water as a function of x, amount used. Express the complement of the following functions in sum-of-minterms form: (a) F(A,B,C,D) = (2, 4, 7, 10, 12, 14) (b) F(x, y, z) = T(3, 5, 7) Q2. bd′+acd′+ab′c+a′c′. • However, it may not be minimal. Complement function will be equal to the sum of minterms missing from the given function. Expert-verified. Maxterm. Minterm can be understood as a product of Boolean variables (in normal form or complemented form). The sum denotes the ORing of these terms. During the first step of the method, all prime implicants of a function are. Referring to the above figure, Let’s summarize the procedure for writing the Sum-Of-Products reduced Boolean equation from a K-map: Form largest groups of 1s possible covering all minterms. Question: Given the function y=ab+a′ a) What's the sum-of-minterms form? b) Construct the truth. Express the following function as the sum of minterms. Since the function can be either 1 or 0 for each minterm, and since there are 2^n minterms, one can calculate all the functions that can be formed with n variables to be (2^(2^n)). The canonical Sum-of-Products (SOP) and Product-of-Sums (POS) forms can be derived directly from the truth table but are (by. The answer should list the minterms as m0+m1+m2. Obtain the truth table of the function F = (A+ C)(B + C) and express the function in sum of minterms and product of maxterms. 2. Minterm definition: In Boolean algebra, a product term in which each variable appears once (in either its complemented or uncomplemented form). 4: let F = A'C + A'B + AB'C + BC a) Express it in sum of minterms. It is represented as the sum-of-minterms (expression 1), together with the don’t care conditions d (expression 2) as shown below:(a) Construct the truth table. Each of these three product statements is a minterm—a term that is True (1) for exactly one combination of inputs. CSE370, Lecture 51 Canonical forms! Last lecture " Logic gates and truth tables " Implementing logic functions " CMOS switches Today™s lecture " deMorgan™s theorem " NAND and NOR " Canonical forms #Sum-of-products (minterms) #Product-of-sums (maxterms) 2 de Morgan™s theoremObtain the truth table of the following functions and express each function in sum of minterms and product of maxterms: a) (xy + z) ( y + xz) b) (A’+ B) (B’+C) c) y’z + wxy’ + wxz’ + w’x’z 3. Transcribed image text: 2. Example: x'yz' + xyz for the Sum-of-minterms Terms should be written in ascending order. Simplify the function using K-map. a) 3 Variables: A(x,y,z)=m0+m5+m6+m7 b) 3 Variables: B(x,y,z)=m0+m2+m3+m5+m6+m7 c) 4 Variables:o For n=2 where the variables are x and y, there are 4 minterms in total: xy, xy’, x’y, x’y’. I have a question regarding the process of finding minterms. The grouping of 0’s result in Product of Sum expression & the grouping of 1’s result in Sum of Product expression. 10. Show an algebraic expression in sum of minterms form. How to simplify from $ar{c}(ar{a}+b)+a$ to $ar{c}+a$ Hot. (d) Express E and F in sum-of-minterms algebraic form. 4: let F = A'C + A'B + AB'C + BC a) Express. This page titled 8. Example if we have two boolean variables X and Y then X + (~Y) is a maxterm we can express complement ~Y as Y’ so, the above maxterm can be expressed as X + Y’ So, if we have two variables then the maxterm will consists of sum of both the variables. 10 of a logic function f of three variables. In SOP (sum of product) form, a minterm is represented by 1. So a 4-variable k-map will have 16. Note: Type x for x 385678 25595020 Jump to. F (a,b,c,d)=a′b′+d′c′+ad+bc. * (b+cd)(c+bd) B. 1. F(a, b, c) = (A & B & C) | (A & B & (~C)) | (A & (~B) & C) | (A & (~B) & (~C)) which is then perfectly simplified to F(a, b, c) = AWe generally use the ∑ (sigma) notation to represent minterms. Any Boolean function that expressed as a sum of minterms or as a product of max terms is said to be in its canonical form. Truth table: This relation can also be expressed as a table giving input combinations in one column and corresponding output in the other and this representation is called a truth table representation. 3) Simplify the following Boolean functions, using three-variable maps:We have minterms. Mano, 3rd Edition 3. Each row of a table defining a Boolean function corresponds to a minterm. DLD 2. Learn how to map minterms and maxterms for logic reduction problems using Karnaugh maps and Product-Of-Sums expressions. You'll get a detailed solution from a subject matter expert that helps you learn core concepts. You answer should be in the format of sum of minterms. Show a minimum POS expression (f: 2 solutions, 3 terms, 6 literals; g: 1 term. A sum term containing all the input variables of the function in either complemented or uncomplemented form is called a maxterm. Write it as a product of maxterms. (A*-B)+ (-A*B) = XOR. e. Sum of products and product of sums are methods of representing boolean expressions. Now we have to obtain the PDNF (Principal disjunction normal form) and PCNF (Principal conjunction normal form) with the help of equivalence. The sum of minterms (SOM) form; The product of maxterms (POM) form; The Sum of Minterms (SOM) or Sum of Products (SOP) form. A function is given by f (x,y,z)= (x) (y+z) Write this expression as a sum of minterms. A minterm is a product of all variables taken either in their direct or complemented form. (for example, after you have combined the first two terms to A′B′D′ A ′ B ′ D ′, you can do. • Each individual term in the SOP form is called Minterm. Obviously, this requires a methodology. If the variable value is 0, take its complement. For maxterms this is the location of 0 s, as shown below. Each of these three product statements is a minterm—a term that is True (1) for exactly one combination of inputs. Identify minterms or maxterms as given in the problem. F = ABC + ABD + ABC + ACD (b) F= (W+X+Y) (WX + Y. 1b it is impossible to represent the minterms x1 x2 x3' x4' and x1 x2 x3 x4'. a) 3 Variables: A (x,y,z)=m3+m4+m6+m7 b) 3 Variables: B (x,y,z)=m0+m2+m4+m5+m6 c) 4. This is a normal form of SOP, and it can be formed with grouping the minterms of the function for which the o/p is high or true, and it is also called as the sum of minterms. Final answer. 2 is the complement of the corresponding minterm A B ¯ C Plotting a maxterm on a Karnaugh map requires further consideration. (c) Using Boolean algebra, derive a simplified sum of products expression. Note: For n-variable logic function there are 2 n minterms and 2 n maxterms. Groups must be a power of 2. Please clearly show your Karnaugh maps, circling, and place your final Boolean equation on the line provided. Final answer. Then make sure that every term contains each of a, b, and c by using the fact that x + x ′ = 1. Convert to sum-of-minterms form: ac + a'c' Consider a function with three variables: a, b, c. Check out a sample Q&A here. For SOP put 1’s in blocks of K-map respective to the minterms (0’s elsewhere). 2. So, every minterm has three literals. Truth table: This relation can also be expressed as a table giving input combinations in one column and corresponding output in the other and this representation is called a truth table representation. 20) Complement of a function: The complement of a function expressed by a Sum of Minterms is Changed to Product of Maxterms with the same indices. The Sum-Of-Products solution is not affected by the new terminology. and B workers work, gives "logic 1" output if there are only 2 people in the workplace, first obtain the truth table to create the circuit that expresses this situation, then POS Write the function (according to the maxterms) and then draw the circuit of this function. Problem: Find the minterms of the following expression by first plotting each expression on a K-map: a) F(X,Y,Z) = XY + XZ + X’YZ b) F. Who are the experts? Experts have been vetted by Chegg as specialists in this subject. A Product-OF-Sums solution is completed in the usual manner. B’ 0 1 m1 = A’ . egin {tabular} {|c|c|c|c|} hlinex & y & z & f (x,y,z) hline 0 & 0. c. Key points: Minterms are values giving the output 1. – Each maxterm has a value of 0 for exactly one combination of values of variables. (d) Draw the AND-OR circuit for the expression in part (c). Transcribed Image Text: Write down an expression for F(X,Y,Z) in (a) sum of minterms form and (b) product of maxterms form for the truth table below: 4. Final answer. Try focusing on one step at a time. The minterm evaluates to 1 if and only if the values of the variables are set according to the corresponding row of the table. Though, we do have a Sum-Of-Products result from the minterms. Question: Write the following expression as a sum of minterms: f(x,y,z)=xyz^'+x^' z+y, then simplify. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. So the minterms would come out to be 0, 1, 1, 3, 5, and 7. Exercise 5. Truth table (5 points) (5 points) (5 points) (b) F(A, B, C) = (A+B)(A+C')(A'+B'+C) 4. There are two types of canonical forms: SOP: Sum of products or sum of minterms. What if instead of representing truth tables, we arranged in a grid format. For the Boolean functions E and F as given in the following truth table: XYZ 0 (a) List the minterms and maxterms of each function. (cd+b′c+bd′)(b. given a truth table, find a logic circuit able to reproduce this truth table. Example: F := a xor b xor c. Which of the following expresses E in sum-of-minterms form? Show transcribed image text. Advanced Math questions and answers. We form the minterms as intersections of members of the class, with various. Draw the logic diagram, using the original Boolean expression c. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. ABC G minterms m-notation 000 A'B'C' 001 m1 0 1 0 1 100 M4 1 0 1 1 AB'C 11 0 me 1 1 1 1 What is the expression G in sum of minterms form? am₁ + m₂ + m² + M6 + M7 b. Select a next property from the right to apply wy wly:1) w (ly:1). b. For the input/output table, give a Boolean expression that is a sum of minterms and is equivalent to the function defined by the table. (e) Using Boolean algebra, derive a simplified product of sums expression. • In Minterm, we look for the functions where the output results is “1”. For the following functions, show an algebraic expression in sum of minterms form. Suppose Limor Fried expands her business, Adafruit Industries, to make electric scooters. List the minterms of E- and F-. 2) Example of sum of products form. A Boolean function can be expressed, canonically, as a sum of minterms, where each minterm corresponds to a. Minterms are represented in the SOP. B+C + A•B. Question: Part 3: Circuit Implementation (50 points) Using Logisim, design a 3-input circuit that outputs a “1” when the corresponding binary inputs have odd number of 1's following these steps: 1. Sum of minterms is unique. UPSC IES Final Result 2023 Out on 22nd November 2023! A total of 401 candidates have been recommended for appointment based on written exam and interview marks. which implies that the minimal sum-of-products is given by f = x1 x3' + x2' x3. (Digital_design-__morris_mano-fifth_edition) Boolean functions expressed as a sum of minterms or product of. for C. In this section of Digital Logic Design - Digital Electronics - Karnaugh Map and Minimization MCQs (Multiple Choice Questions and Answers),We have tried to cover the below lists of topics. It represents exactly one combination of binary variable values in the truth table and it has the value 1 1 1 for that combination. 1. 9 find the displayed function expressed as a sum of minterms and also find the function as a product of maxterms. This is obviously so for n = 4. B(A,D,W)=A′D′W′+A′D′W+AD′W′+AD′W+ADWB(A,D,W)=A′DW′+A′D′W+ADW′+AD′W+ADWB(A,D,W)=A′DW+A′D′W+ADW′+AD′W′+ADWB(A,D,W)=A′DW′+AD′W+ADW′+AD′W+A′DW Q7. Question: в с be BC 00 01 001111 al AC ABC Using the following truth tables, write out both the Sum of Minterms and optimized Boolean expression (optimore with Kamaugh mape) for each B lalalalala ABC F 000 0 0 0 1 0. Sum of minterms form •Every function can be written as a sum of minterms, which is a special kind of sum of products form •The sum of minterms form for any function is unique •If you have a truth table for a function, you can write a sum of minterms expression just by picking out the rows of the table where the function output is 1. So, SOP is defined as Sum of Its Min Terms or the other name is Canonical Disjunctive Normal Form. Find the output function of each truth table a. The numbers indicate cell location, or address, within a Karnaugh map as shown below right. Obtain the truth table for the following functions, and express each function in sum-of-minterms and product-of-maxterms form: ( b + c d ) ( c + b d ) Expert Solution. List the. Simplify E and F to expressions with a minimum of literals. Express the complement of the following function in sum of minterms: a) F(A,B,C,D)=∑(0,2,6,11,13,14) b) F(x,y,z)=∏(0,3,6,7)This video provides the solution to the problem: 2. Using truth table find sum-of-minterms and product-of- maxterms form for function F1 b. Get the free "Minterm" widget for your website, blog, Wordpress, Blogger, or iGoogle. ABC + A̅B̅C 2. See Answer. These support the statements shown, but are not proofs thereofbecause they are only an example. View the full answer. Expert-verified. Express f (x, y, z) = x y ˉ + x ˉ yz as a canonical SOM. Select the 1 in the Complement property ata': 1, so that ata' - 1 5. A sum of minterms is a valid expression of a function, while a product of maxterms is not. Though, we do have a Sum-Of-Products result from the minterms. Step 2. Convert to sum-of-minterms form: bc+b'c 3 = Ex: xyz + xyz' + xy'z + xyz Use the true form of the literal first when expanding. A city water service has a base cost of $12 per month plus$1. Now apply DeMorgan's: Not Not f f = Not (AB¯¯¯¯C Or AB¯¯¯¯C¯¯¯¯) = (A¯¯¯¯ Or B Or C¯¯¯¯) And (A¯¯¯¯ Or B Or C) Your given answer for "product of maxterms. This video describes how to Express a boolean function in sum of minterms. • We perform Sum of minterm also known as Sum of. Express E and F in sum-of-minterms algebraic form. b) Find the minimal sum of products expression. Engineering. Example lets say, we have a boolean function F defined on two variables A and B. See examples, procedures, and diagrams for each type of term. Example 2. Since any boolean function can be expressed as a sum of minterms, a decoder that can generate these minterms along with external OR gates that form their logical sums, can be used to form a circuit of any boolean function. Suppose n = 2 (x and y) and, we know ‘0’ represents complements i. Also, it appears the first row is starting from 0, not 1? The Boolean equation description of unsimplified logic, is replaced by a list of maxterms. Though, we do have a Sum-Of-Products result from the minterms. 2. Key points: Minterms are values giving the output 1. Note: Type x' for X 366628. 3 – Minterms for Three Variables. (e) Simplify E and Fto expressions with a minimum of literalsQ: Express each of the following function as a sum of minterms and as a product of maxterms F = x′z +… A: As given, I need to express the given functions as a sum of minterms and product of maxterms. Use Karnaugh maps to simplify the following Boolean functions expressed in the sum of minterms. It is often referred to as minterm expansion or standard sum of products. They are called terms because they are used as the building-blocks of various canonical representations of arbitrary boolean functions. minterm (plural minterms) In Boolean algebra, a product term, with a value of 1, in which each variable appears once (in either its complemented or. ABC̅ + AB̅C + A̅B̅C̅ 5. Obtain the truth table of the following functions, and express each function in sum-of-minterms and product-of-maxterms form: (a) (XY + Z) (Y + XZ) b) (A bar + B) (B + C) (c) WxY bar + WXZ bar + WXY + YZ For the Boolean functions E and F, as given in the following truth table: List the minterms and maxterms of each function. Make rectangular groups. There are 4 steps to solve this one. Given that f1(a,b,c)=∑m(1,4,5) and f2(a,b,c)=∏M(0,2,3), derive the sum of minterms form of thefunction f1+f2. 7. To construct the product of maxterms, look at the value of Not f. Show the un-simplified logic equation for the customizedfunction, expressed as a sum of minterms. 1 . Example: The output values are 0,1,1,0, (and the table is ordered from 00 to 11), so the truth table is: input. A maxterm is a sum. Cox – Spring 2010 The University Of Alabama in HuntPetrick's Method is used for determining minimum sum-of-product (SOP) solutions in a given prime implicants chart. - (P* (-P+Q))+Q = Modus ponens. e. The value for all other combinations is 0 0 0. We tabulate Maxterm combinations. F (a,b,c) = a'c' + a'c + bc'. $\endgroup$ – copper. For example: F = m (2. Any Boolean function can be expressed as the sum (OR) of its 1- min terms. 9: Sum and Product Notation is shared under a GNU Free. This is an introductory video on K-maps in digital electronics series. See Answer See Answer See Answer done loading Final answer. So for x'y' there exists two options of 00- where z is 000 and 001. In order to accurately use the Quine-McCluskey, the function needs to be given as a sum of minterms (if the Boolean function is not in minterm form, the minterm expansion can be found) to determine a minimum sum-of-products (SOP) expression for a function. See the difference between the two expressions, the truth table, the K-map and the model answer for this question on Stack Overflow. For the equation Out=. 1. Expand wx to sum-of-minterms form wxy+wxy' 1. Sum of Product is the abbreviated form of SOP. It can be directly taken from the Truth Table for the function. If each product term is a minterm, the expression is called a canonical sum of products for the function. 1 Answer. List the minterms of E + F and E F. 15 Simplify the following Boolean function F, together with the don't care conditions d, and then express the simplified function in sum-of-minterms form: (a) F(x. 4. . Express F(A, B, C) = A+B+C in standard sum of. Terms and Glossary 0 abcf g 0 0 0 0 1 Exercise Problem 2. ) F (x,y,z)= x'y + x + xyz. 2. The values of Di (mux input line) will be 0, or 1, or nThe name ‘minterm’ derives from the fact that it is represented by the smallest possible distinguishable area on the map. 6(3)(English) (Morris Mano) Question 2 . 0 1 1 0 0 10001 1011 1 1 1 0 1 1 1111 0Canonical Forms: Product of Sums with Two Variables Showing Maxterms Maxterm A B Result M 0 0 0 r 0 M 1 0 1 r 1 M 2 1 0 r 2 M 3 1 1 r 3 The maxterm for a row is the OR of each variable –uncomplemented if it is a 0 and complemented if it is a 1. The minterms with output values of false (-1) were eliminated, leaving only 6 minterms. Question: Q7 4 Points The following questions refer to the Truth Table below Q7. b) The Boolean function G = F 1 F 2 containsonly the minterms that are common to F 1 andF 2. Example of SOP: XY + X’Y’ POS: Product. (c) List the minterms of E + F and E F (d) Express E and F in sum-of-minterms algebraic form. It is represented as the sum-of-minterms (expression 1), together with the don’t care conditions d (expression 2) as shown below: Consider a logic function F, which has four inputs A, B, C and D. Be sure to label each theorem used at each step. 2. Publisher: PEARSON. (a) minterms of E: X Y Z , X Y Z, X YZ , XY Z 0,1,2,5This video describes how to Express a boolean function in sum of mintermsThe sum of the minterms is known as sum of product. 7. Using the minterms for which the function is equal to 1, the function can be written explicitly as follows:Minterms. Expert Answer. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Please clearly show your Karnaugh maps, circling, and place your final Boolean equation on the line provided. Question: Given the following Boolean Function F (A,B,C) = AB +B' (A'+C') Determine the canonical form for the SOP (sum of minterms) and POS (product of maxterms). 100% (1 rating) Transcribed image text: Discrete Mathematics home > 5. we need to simplify the function in the sum of minterms we will use the K-Map to simplify the function the K-Map is a very useful tool to simplify long boolean expressions into simplified form in a very systematic approachKarnaugh map can produce Sum of product (SOP) or product of Sum (POS) expression considering which of the two (0,1) outputs are being grouped in it. (b) List the minterms of E bar and F bar. 1: Convert the table to a sum-of-minterms. 2 pg. Q. Express the following function as a sum ofsum of minterms.